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Results

Permutation (nPr)

P(n,r) = n! / (n - r)!
720 possible arrangements
n!: 3,628,800
(n-r)!: 5,040

Combination (nCr)

C(n,r) = n! / (r! × (n - r)!)
120 possible combinations
r!: 6
(n-r)!: 5,040

Key Concepts

Permutations (nPr)

An ordered arrangement of objects where the sequence matters. For example, the finish order in a race (1st, 2nd, 3rd) is a permutation.

P(5,3) = 5! / (5-3)! = 60

Combinations (nCr)

A selection of objects where order doesn't matter. For example, selecting a committee of 3 people from 10 candidates.

C(5,3) = 5! / (3! × (5-3)!) = 10

Practical Examples

Permutation Example

Scenario: How many ways can 4 horses finish a race in 1st, 2nd, and 3rd place?

Solution: P(4,3) = 4! / (4-3)! = 24 possible finishing orders

Combination Example

Scenario: How many different 3-topping pizzas can you make from 8 available toppings?

Solution: C(8,3) = 8! / (3! × (8-3)!) = 56 possible combinations

Professional Applications

Bioinformatics

Calculating possible DNA sequence combinations

Cryptography

Determining password strength possibilities

Statistics

Probability calculations and sampling methods